Luis Bethencourt Correa
CD BUBILLA · Vi Copa Canaria Veteranos Tene · 2ª Categoría Masculina
Team: CD BUBILLA →Pair 1
0
Points
1
Matches
0%
Wins (0-1)
0%
Sets won (0-2)
📋 Performance report
AI analysis of all their stats: strengths, areas to improve, mental side, progress and tips for the captain.
Best partners
No data yet
Worst partners
1.Jonay Zebensui Herrera Santana
1 matches together · 0% won · 0-1
Compared with their team and division
3 of 12 in their team · 5 of 116 in their division
Points
0296
Wins
0%83%48%
Sets won
0%79%48%
Matches
12.52.4
More stats
This season in their division, against their team's average and the division's. Green: better than the division average; red: worse.
| Luis | Team avgTeam | Division avgDivision | |
|---|---|---|---|
| Wins away | 0%0/1 | 83% | 47% |
| Against the rest | 0%0/1 | 83% | 59% |
| Ties decided by one pointTies decided by a single point (3-2, 2-1). | 0%0/1 | 63% | 46% |
| Current streak | 1 lost | - | - |
| Best winning streak | 0 | 2.1 | 1.2 |
| Share of team winsShare of the team's won pairs that they won. | 0% | 16.7% | 15.5% |
| AvailabilityTeam ties in which they played. | 20%1/5 | 50% | 46% |
| Different partners | 1 | 2.2 | 1.9 |
| First half | 0%0/1 | 75% | 50% |
By turn and court
Win % on each court they have played.
| Luis | Team avgTeam | Division avgDivision | |
|---|---|---|---|
| Pareja 1 | 0%0/1 | 60% | 55% |
Match history · 1
| D | TR PADEL CLUB GALEON A 4 Jul 2026 · with Jonay Zebensui Herrera Santana | C1 |
All their partners · 1
| Player | W-L | Win % | Usually play |
|---|---|---|---|
| Jonay Zebensui Herrera Santana | 0-1 | 0% | C1 |
Teammates
Juan Manuel Hernandez Garcia · 172Bruno Manuel Febles Clemente · 172Jose Angel Gonzalez Fajardo · 0Ignacio De Paz Aguirre · 0Juan Francisco Corominas Gonzalez · 0Humberto Garcia Matos · 0Alejandro De Luis Gestoso · 0Roberto Escuela Losada · 0Fernando Miranda Burgos · 0Israel Chinea Gonzalez · 0Alberto Luis Delgado Del Toro · 0Carlos Alba Martinez · 0Jonay Zebensui Herrera Santana · 0Javier Togores Guigou · 0
