Adrian Ruiz

TUPADEL ALCORA · 4ª Masculina · Grupo K Castellón

Season 2025-2026
Team: TUPADEL ALCORA →Pair 3
0
Points
3
Matches
33%
Wins (1-2)
33%
Sets won (2-4)

📋 Performance report

AI analysis of all their stats: strengths, areas to improve, mental side, progress and tips for the captain.

Best partners

1.Eric Pallares

1 matches together · 100% won · 1-0

Worst partners

1.Jorge Garces

1 matches together · 0% won · 0-1

2.Javier Olivas

1 matches together · 0% won · 0-1

Compared with their team and division

1 of 12 in their team · 1 of 166 in their division

Points
Adrian
0Team average
0Division average
0
Wins
Adrian
33%Team average
76%Division average
47%
Sets won
Adrian
33%Team average
70%Division average
47%
Matches
Adrian
3Team average
5Division average
3.7

More stats

This season in their division, against their team's average and the division's. Green: better than the division average; red: worse.

AdrianTeam avgTeamDivision avgDivision
Wins at home50%1/276%53%
Against the top 30%0/169%25%
Against the rest100%1/189%58%
Ties decided by one pointTies decided by a single point (3-2, 2-1).0%0/155%50%
Current streak1 won--
Best winning streak12.91.4
Share of team winsShare of the team's won pairs that they won.4.5%16.7%11.9%
AvailabilityTeam ties in which they played.22%2/950%37%
Different partners23.52.8
First half0%0/179%49%
Second half100%1/187%50%

By turn and court

Win % on each court they have played.

AdrianTeam avgTeamDivision avgDivision
Pareja 20%0/167%50%
Pareja 3100%1/189%50%

Match history · 3

DPEDREGUER PADEL COBERT 2
8 May 2026 · with Javier Olivas
C3
VMÁS QUE PADEL
27 Mar 2026 · with Eric Pallares
C3
DCLUB DE PADEL BURRIANA-ESPADEL 4 MASCULINO
17 Jan 2026 · with Jorge Garces
C2

All their partners · 3

PlayerW-LWin %Usually play
Eric Pallares1-0100%C3
Jorge Garces0-10%C2
Javier Olivas0-10%C3

Teammates

Ramón Trilles · 0Daniel Cordero · 0Eric Pallares · 0Joan Roda · 0Jorge Renau · 0Javier Olivas · 0Jorge Rebollo · 0Daniel Chiva · 0Aitor Garcia · 0Jorge Garces · 0Marc Maso · 0Jorge Tena · 0